29.NA January 2019 Q.7(B)

A ship of 14900 tonnes displacement have a shaft power of 4460 KW at 14.55 knots. The shaft power is reduced to 4120 KW and fuel consumption at same displacement is 541 Kg/h. Calculate the fuel coefficient of the ship.

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Given 

△ = 14900 t
SP2 = 4460 KW
V2 = 14.55 knots
SP1 = 4120 KW
Fuel consumption = 541 Kg/h

To find

Fuel coefficient

Solution

As we know that SP directly proportional to Speed3
                                   SP directly proportional tp V3

                                               SP2 / SP1 = (V2 / V1)³  
                                            4460 / 4120 = (14.55 / V1)³
                                                          V1 = 14.17 knots

At 14.17 knots fuel consumption = 541 Kg/h 
                                                    = 541 x 24 x 10^-3
                                                    = 12.98 t / day

Fuel coefficient =  (△^2/3 x V1³ ) / Fuel consumption tonne per day 
                         = (14900^2/3 x 14.17³) / 12.98

                           

Fuel coefficient   = 132726