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15 February 2019

31.NA January 2019 Q.5(B)

February 15, 2019 Posted by AK 2 comments
A ship of displacement 10010 t has a container of 10 t Kg = 7.5m. The container is shifted transversely. A pendulum of length 7.5m deflects through 13.5 cm. GM = 0.76m , KM = 6.7m. Find the distance through which container is shifted. Also find new Kg if container is moved.

If you are noticing some error in problems kindly comment below.Thanks

Given 

Displacement △ = 10010 t
GM = 0.76m
KM = 6.7m
m = 10 t
Kg = 7.5m
Length of pendulum l = 7.5m
Deflection a = 13.5 cm

To find

1. Distance d
2. New Kg

Solution

1. Kg of the ship = KM - GM
                           = 6.7 - 0.76
                           = 5.94m

    GM  = (m x d x l) / (△ x a )
    0.76  = (10 x d x 7.5) / (10010 x 0.135)
          d = 13.69m

2. New Kg = Total moment / Total displacement

                  = ((△ x Kg of ship) - (m x Kg of container)) / (△ - m)
                  = ((10010 x 5.94) - (10 x 7.5)) / (10010 - 10)
    New Kg = 5.938m

  

2 comments:

  1. 31 NA Jan 2019 Q5(B).
    Pls conform in dieselship question DEFLECTION given in meter,but now taken as in cm. Pls check.

    ReplyDelete
    Replies
    1. Length of pendulum is 7.5m. The deflection can't be 13.5m. It can be 13,5 cm or mm only.

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