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13 February 2019

33.MET January 2019 Q.10(B)

February 13, 2019 Posted by AK 5 comments
A 4-pole machine running at 1500 r.p.m. has an armature with 80 slots and 6 conductors per pole. The flux per pole is 6 x 106 lines. Determine the terminal e.m.f. of d.c. generator if the coils are lap connected. If the current per conductor is 100 A, determine the electrical power

                 If you are noticing some error in problems kindly comment below.Thanks

Given

No of poles, P = 4
Rpm, N = 1500
No of slots = 80
Conductor per pole = 6
Flux per pole ø =  0.06 Wb
Current per conductor I = 100 A

To find

1. Terminal EMF
2. Power

Solution

Total number of conductors Z = 80 x 6
                                                 = 480

Total current = 100 x 4 = 400 A

No of parallel path = No of poles (LAP WINDING)
                            A = P = 4

1. Terminal EMF , E = ( ø x Z x N/ 60) x (P /A)
                                 = (0.06 x 480 x 1500 / 60 ) x (4 / 4)
                                 = 720 V

2. Power = E x I
               = 720 x 400
               = 288 kW

5 comments:

  1. Here no of conductors=6 pole/conductor,so,z=6*4=24
    If question given 6conductor/slots then z=80*6=480
    Z=

    ReplyDelete
    Replies
    1. Please confirm. In all types of these problems in Thereja book it is considered Z = Total no of conductors with regard to no of slots. They considered Z irrespective of poles.

      Delete
  2. same problem above plz suggest me also.

    ReplyDelete
    Replies
    1. Please confirm. In all types of these problems in Thereja book it is considered Z = Total no of conductors with regard to no of slots. They considered Z irrespective of poles.

      Delete
  3. Anant Singh Dhanoa12:22 pm, January 19, 2020

    It is a little confusing, not only because of Z but also we have 100 A per conductor as in question. But we take it as 100 A per pole. Confusing.

    ReplyDelete