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31 January 2021

106.NA November 2020 Q.10(b)

January 31, 2021 Posted by AK No comments

A propeller 6m diameter has a pitch ratio of 0.9, BAR 0.48 and, when turning at 110 rev/min, has a real slip of 25% & wake faction 0.30. If the propeller delivers a thrust of 300 kN & the propeller efficiency is 0.65, calculate:

i. Blade area ii. Ship speed iii. Thrust power iv. Shaft power v. Torque

IF YOU ARE NOTICING ANY ERROR KINDLY COMMENT BELOW

Given

D = 6 m

p = 0.9

BAR = 0.48

N = 110

s = 0.25

w = 0.30

T = 300 kN

ηp = 0.65


To find

i. Blade area 

ii. Ship speed 

iii. Thrust power 

iv. Shaft power 

v. Torque

 

Solution

i) We know that BAR = Ad  / {(π/4) x D2)

                            0.48 = Ad / {(π/4) x 62)

                            0.48 = Ad / 28.26 

           Blade area, Ad =  13.56 m2


ii) We know that pitch ratio, p = P / D                                            

                                           0.9 = P / 6 

                                  Pitch , P = 5.4 m  

 

Theoretical speed , Vt = P x N

                                    = 5.4 x 110 

                                     = 594 m/min = 9.9 m/sec

 

Real slip , s = (Vt - Va) / Vt

            0.25 = (9.9 - Va) / 9.9

          2.475 = 9.9 - Va

 Speed of advance, Va = 7.425 m/sec

 

Wake fraction, w = (V - Va) / V

0.30 = (V - 7.425) / V

0.3 x V = V - 7.425

0.7 x V = 7.425 

Ship speed , V = 10.60 m/sec = 10.60 x (3600/1852) = 20.60 knots


iii) We know that thrust power, tp = Thrust x Speed of advance

                                                       = 300 x 7.425

                                                       = 2227.5 kW

 

iv)  We know that thrust power, tp = Delivered power x propeller efiiciency

                                           2227.5 = dp x 0.65

                                                  dp = 3426.92

And shaft power , sp = dp / transmission efficiency

As in problem nothing mentioned about transmission efficiecy, it is considered as negligible.

So Shaft power , sp = 3426.92 kW

 

v) We know that dp = Torque x 2 x π x n 

3426.92 = T x 2 x π x (110/60)              {n = N/60}

3426.92 = T x 11.51

Torque , T = 297.73 kN m



      

 

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