actually SM is taken as 1 4 1 1 4 1 like this. So for first 1 4 1 , we take half of SM multiplier as 0.5. For 2nd 1 4 1 , we dont have to take half of 1. So SM will be 0.5 2 0.5 1 4 1. So resultant will be 0.5, 2, 1.5.
Bro 1.2/3 is 0.4 u have written 0.41 n also Ab answer is incorrect pls chk with 0.4 Also displacement calculations 1st part can u chk bcz in other books dey have calculated in m3.
what is the reason you took SM ( 0.5, 2, 1.5) instead of 1,4,2,4 ?
ReplyDeletePlease check the drafts given. common interval is 1.2 But for 0 t0 0.6 and 0.6 t0 1.2 it is half of the interval. so SM also will be half
Deletethanks for correction. But as half of 1,4,2, .. are .5,2,1.. so why you used 1.5 ?
Deleteactually SM is taken as 1 4 1
Delete1 4 1 like this. So for first 1 4 1 , we take half of SM multiplier as 0.5. For 2nd 1 4 1 , we dont have to take half of 1. So SM will be
0.5 2 0.5
1 4 1. So resultant will be 0.5, 2, 1.5.
Bro 1.2/3 is 0.4 u have written 0.41 n also Ab answer is incorrect pls chk with 0.4
ReplyDeleteAlso displacement calculations 1st part can u chk bcz in other books dey have calculated in m3.