185.MET June 2022 Q.10(b)

  An AC voltage of 24 V is connected in series with a silicon diode and load resistance is 500 ohm having forward resistance 10 ohm. Calculate the peak output voltage.

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SOLUTION

As the diode is connected in series the effective resistance 

R = RL + Rf

    = 500 + 10

    = 510 ohm

V = 24 V

Peak current = V / R

                     = 24 / 510

                     = 0.047 A

Peak output Voltage = Peak current x RL

                                 = 0.047 x 500

                                 = 23.5 V