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07 February 2024

195.MET September 2022 Q.6(b)

February 07, 2024 Posted by AK No comments

Three impedances Z=5+j4 are connected in the form of a delta to the three loads of a balanced 3- phase circuit. The line voltage is 120 Volts. Find (a) The phase current, (b) Power factor, (c) The volt-ampere in the circuit


In a delta connected 3 phase system

Vline = Vphase

Iline = √3 Iphase

Iphase = Vline / Z


Inductive reactance X = 4 ohm

Resistane R = 5 ohm

Impedane Zph = 5+j4 = 6.40∠ 38.66o


1) Iph = Vline / Z

           = 120 / 6.40

           = 18.75 A


2)  φ = 38.66

     Power factor cos φ = 0.78


3)  So Vline = Vph = 120 V

           Iph = 18.75 A 

Volt ampere = Vph x Iph

                    = 120 x 18.75 = 2250 VA    

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