A 3phase, 4pole 24 slot alternator has its armature coils short pitched by one slot. Find the distribution factor and pitch factor
If you are noticing some error in problems kindly comment below.Thanks
Given
No of pole = 4
No of slot = 24
To find
1. Distribution factor
2. Pitch factor
Solution
No of slot per pole, n = 24 / 4
= 6
Angular displacement between slots β = 180 / n
= 180 / 6
= 30 deg
No of slot/phase/pole, m = 24 / (3 x 4)
= 2
1. Distribution factor Kd = (Sin mβ/2) / (m sin β/2)
= (Sin 2 x 30/2) / (2 x Sin 30/2)
= 0.965
Armature coils are short pitched by one slot. Therefore angle a is same as that of B.
2. Pitch factor Kc = cos α /2
= cos 30/2
= 0.965
If you are noticing some error in problems kindly comment below.Thanks
Given
No of pole = 4
No of slot = 24
To find
1. Distribution factor
2. Pitch factor
Solution
No of slot per pole, n = 24 / 4
= 6
Angular displacement between slots β = 180 / n
= 180 / 6
= 30 deg
No of slot/phase/pole, m = 24 / (3 x 4)
= 2
1. Distribution factor Kd = (Sin mβ/2) / (m sin β/2)
= (Sin 2 x 30/2) / (2 x Sin 30/2)
= 0.965
Armature coils are short pitched by one slot. Therefore angle a is same as that of B.
2. Pitch factor Kc = cos α /2
= cos 30/2
= 0.965
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